Fragments of what I learnt about Binomial Probability suggest that the chances of picking exactly 5 of 8 years to end in 6 is 1 in 2500 approx. (not 1 in 100,000 because you have to allow for the remaining three years not ending in 6 and also that the five can appear in any order; 8C5 * 0.1^5 * 0.9^3) . If you alter the question to ask, what are the chances that the years should end in the same digit, not necessarily a 6, it's one in 250.
You would get 1 in 100,000 if the scenario was, select a digit, then select only five years at random to match that digit.
It wouldn't be a probability problem if the answer wasn't disputed, but this result is at least supported by AI.
Originally Posted by: DEW